![]() ![]() Now sum forces normal and tangential to side AA. Solution: Make cut AA so that it just hits the bottom right corner of the element. The tank of Problem 2.97 is accelerated so that pB 60 kPa. Find the shear and normal stresses on plane AA cutting through at 30°. Find the force on the bottom of the cylinder of: For the cylinder shown in Fig. Let, = Inclination of the lock gate with the normal to the walls of the lock.įrom the geometry of the figure ABO, we find that it is an isosceles triangle having its angles OBA and OAB both equal to. The force P needed to hold the gate in the position shown is nearest: (A). Let, P and F meet at O, then R must pass through this point. Since the gate AB is in equilibrium, under the action of the above three forces, therefore they will meet at one point.
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